Define Carnot Theorem and also give its
proof.
Carnot theorem states that no heat engine working in a cycle
between two constant temperature reservoirs can be more efficient than a
reversible engine working between the same reservoirs. In other words it means
that all the engines operating between a given constant temperature source and
a given constant temperature sink, none, has a higher efficiency than a
reversible engine.
Proof:
Suppose there are two engines EA and EB operating between the given source at temperature T1 and the given sink at temperature T2.
Suppose there are two engines EA and EB operating between the given source at temperature T1 and the given sink at temperature T2.
Let EA be any irreversible
heat engine and EB be any reversible heat engine. We have to prove that efficiency
of heat engine EB is more than that of heat engine EA.
Suppose both the heat engines receive same
quantity of heat Q from the source at temperature T1. Let W A and WB be the work output
from the engines and their corresponding heat rejections be (Q – WA)
and (Q – WB) respectively.
Assume that the efficiency of the irreversible engine be more
than the reversible engine i.e. ηA > ηB.
Hence,
WA /Q>WB /Q
I.e. WA > WB
WA /Q>WB /Q
I.e. WA > WB
Now let us couple both the engines and EB is reversed which will
act as a heat pump. It receives (Q – WB) from sink and WAfrom
irreversible engine EA and pumps heat Q to the source at temperature
T1. The net result is that heat WA – WB is taken from sink and
equal amount of work is produce. This violates second law of thermodynamics.
Hence the assumption we made that irreversible engine having higher efficiency
than the reversible engine is wrong.
Hence it is concluded that reversible engine working between
same temperature limits is more efficient than irreversible engine thereby
proving Carnot’s theorem.
The max efficiency of a any heat engine is 1-(tempHot/tempCold. This is simply not true. During the cooling phase, simply cool the gas with a Stirling Engine
ReplyDeleterather than the environment.
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